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About Me Member Deviously Deviant fungorillaMale/Malaysia Recent Activity Deviant for 3 Years
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Bluek

Fri Aug 18, 2006, 4:43 AM

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:iconthe-final-i:
:wave: hello and welcome to dA. :)

--
:
E^2= (p^2c^2)+([Δm^2]c^4)
which implies that
E= [mc^2]/[<sq. root>1-(v^2/c^2)]
when p=0 (in eq 1, or in 2 rearranged to 1])
E=mc^2
[as rest mass cannot be attained, p can never=0, so E should, not always be calculated as = mc^2].

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